Question
A point charge $q=+3.0$ nC moves through a potential difference $\Delta V=V_{\mathrm{f}}-V_{\mathrm{i}}=+25 \mathrm{V} .$ What is the change in the electric potential energy?
Step 1
Step 1: The change in electric potential energy is given by the formula: \[ \Delta U = q \Delta V \] where \( \Delta U \) is the change in electric potential energy, \( q \) is the charge, and \( \Delta V \) is the potential difference. Show more…
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