Question
a point on the terminal side of an angle $\theta$ in standard position is given. Find the exact value of each of the six trigonometric functions of $\theta .$$$(-1,-2)$$
Step 1
We can use the formula for r which is $r = \sqrt{x^2 + y^2}$. Substituting the given values into the formula, we get: $r = \sqrt{(-1)^2 + (-2)^2} = \sqrt{1 + 4} = \sqrt{5}$ Show more…
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