Question
a point on the terminal side of an angle $\theta$ in standard position is given. Find the exact value of each of the six trigonometric functions of $\theta .$$$(2,-2)$$
Step 1
Here, the point given is $(2,-2)$, so $x=2$ and $y=-2$. Substituting these values into the formula, we get $r=\sqrt{2^2+(-2)^2}=\sqrt{4+4}=\sqrt{8}$. Show more…
Show all steps
Your feedback will help us improve your experience
Urjeet Deshmukh and 51 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
a point on the terminal side of an angle $\theta$ in standard position is given. Find the exact value of each of the six trigonometric functions of $\theta .$ $$(-1,-2)$$
Trigonometric Functions
Trigonometric Functions of Any Angle
a point on the terminal side of an angle $\theta$ in standard position is given. Find the exact value of each of the six trigonometric functions of $\theta .$ $$\left(\frac{\sqrt{2}}{2},-\frac{\sqrt{2}}{2}\right)$$
a point on the terminal side of an angle $\theta$ in standard position is given. Find the exact value of each of the six trigonometric functions of $\theta .$ $$\left(-\frac{\sqrt{2}}{2},-\frac{\sqrt{2}}{2}\right)$$
Transcript
600,000+
Students learning Algebra with Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD