00:01
In this question, a point on the terminal side of an angle theta is given to us, let's call that point as p, which is 3 comma minus 3.
00:12
And we are supposed to find the 6 trigonometric function for this angle theta.
00:17
So let's plot this point on the coordinate axis plane.
00:20
We have x -axis and y -axis.
00:23
The point p is in the fourth quadrant.
00:27
So if we join the origin with p, this is the angle theta.
00:32
And the distance op is r.
00:35
So from the given coordinates, we can see that the value of x is 3 and the value of y is minus 3.
00:42
So the value of r is given by under root of x square plus y square.
00:49
So if we substitute the values, we get r is equal to under root of 3 square plus minus 3 square.
00:56
So r is equal to under root of 80, which implies the value of r.
01:02
Is 3 root 2.
01:05
Now we can write the trigonometric functions...