00:01
Okay, now we do problem 141.
00:04
So 141, first of all, you have to convert sulfur, so far from 3 % of 10 power 2 matrix to ground of sulfur.
00:15
How can we do? my amount of sulfur, you have to convert this amount of sulfur, only 3 % in this amount of matrix to gram.
00:26
So you get 3 .0 times 6, 106 gram, suffer.
00:32
Why i convert to gram because when you write equation, you do stoichiometry.
00:37
We know the modern mass is gram, not kilogram, not metric strength, so you have to convert it first.
00:43
And then you write equation, you calculate stochometry, you find 6 .0, time 0, 10, 0, 0, 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 06 dioxide.
00:56
And then you have to convert it to matrixons again because the acid 0xxxxxxxx...