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In this exercise, we have two particles, one proton and one delteron, that are incident on a barrier that has a height of 10 mega -electrum volts and a thickness of 10 femtometers.
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Both the delteron and the proton have a kinetic energy of 3 mega -electron volts.
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Our goal in question a is to find what particle has the greatest probability of tunneling.
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Here in red, i have written some information that is going to be useful for us.
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So first, we have the probability of tunneling as proportional to the exponential of minus 2 kappa times a.
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A is the width of the barrier.
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That's the size of the barrier.
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And kappa is equal to the square root of two times the mass of the particle divided by h bar square.
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Times u0 u0 is the height of the barrier minus the kinetic energy of the particle so notice that since the probability is proportional to the exponential of minus 2 kappa a then whichever particle has the smallest kappa has the greatest probability and notice that kappa for the delteron is the square root of 2 times the mass of the delteron, which in the mass of the delteron itself is 2 times the mass of the proton, divided by h -bar -squared times u0 minus the kinetic energy.
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Notice that the kinetic energy is the same for both the electron and the proton.
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Kappa of the proton is two times the mass of the proton divided by h squared u0 minus e.
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So from here we can see that kp, that kpa p, which is the kappa for the proton, is smaller than kappa for the delta.
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And with this, we have that the probability of tunneling for the proton is greater than the probability of tunneling for the delteron.
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So the proton has the greatest probability.
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In question b, we have to find the ratio between the probability of tunneling for the proton and the probability of tunneling for the delterent.
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So this is equal to the exponential of 2, of minus 2, kappa p a divided by the exponential of minus 2 kappa d a, which is equal to the exponential...