00:01
In this problem we have two vectors, one from the initial and one for the final velocity.
00:06
And we know that four seconds passed between one stage and the other.
00:11
And first in part a we want to find the average acceleration.
00:15
So let's define what average acceleration really means.
00:21
That is the final velocity minus the initial velocity over the change in time.
00:31
So let's apply this equation to each of the component.
00:34
Of the vectors.
00:37
First, with the x components, you can say that the acceleration is going to be negative 2 minus 4 all over 4 seconds.
00:52
And that is going to give us negative 1 .5.
01:01
Then let's go to the y component.
01:08
There we have negative 2, negative times negative 2, that is going to be plus plus 2 over 4.
01:17
This gives us 0, and then we have k -hap, which is going to be equal to 5 minus 3 over 4.
01:38
And that is going to give us 0 .5.
01:43
Now we can write this in vector notation and say that the average acceleration is equal to negative 1 .5.
01:56
I had no y component and finally 0 .5 kha.
02:08
And let's remember that these two are in meters per second squared.
02:16
All right.
02:17
Now in part b we want to find the magnitude of the average acceleration.
02:24
And the magnitude of any vector is simply going to be the square root of its components squared and added...