00:01
In this question, we are given this situation.
00:05
So we have a proton, okay, it has a velocity at t1, it has a velocity of vx, i, head, plus vy, j heads, plus 2 ,000 kheats meters per second, and then it is moving in magnetic field in a region of uniform magnetic field that has 0 .01 ihead minus 0 .02 j head plus 0 .03 k hat tesla and the magnetic force on the proton is 4 .0 times 10 to the power negative 17 newton's ihad plus 2 .0 times 10 to the negative 17 mutants j hat.
01:18
So we want to find the value of vx and vy at this instance.
01:25
So to solve this question we'll be using fb equals to qv cross b.
01:38
So we'll calculate qv cross b first.
01:45
So this is equal to e as the charge of the proton.
01:49
Then b is vx, i -had plus vy, j -had, plus 2 ,000 k -hat, cross with 0 .01 .1.
02:04
Ihed minus 0 .02 j hat plus 0 .03 k hat.
02:13
Okay so when you do this cross product okay you can write it in the determinant form okay so you have i j k and then bx y y y 2000 and then you have 0 .01, negative 0 .02, and then 0 .03.
02:41
Alright...