00:01
In this question, we have a proton, moving in a uniform magnetic view, and the magnetic field is pointing in the ihead direction.
00:22
And then it has a initial velocity of v equals to v0x ihad plus v0 .j heads.
00:32
We want to find the velocity v at any later time t of the proton.
00:38
So to do this question, we're using f equals to qv cross b.
00:53
So here b is just any, just b x, y, b, z.
01:00
Okay, and then b is the i hat.
01:05
So b cross b, we just be, i, using the determinant.
01:13
Method okay so we are going to get b times zero vc minus v y okay right so our fb which is be our very deep force okay which is be e times b plus b which is e b z j hat minus v y k hat okay and then using newton second law f equals to m which is m times dv x d t i head plus dby d t j head plus d b z d t k hat okay so comparing components we have dvx d t equals to zero and then dv y d t equals to e b bd t equals to e b over m v z and then d v z d t is negative e b over m v y okay so we can actually find we can differentiate we write one more time with respect to t so the rewind d t square is equal to ebb over m divv z d t and div z d t is negative e b over m v y so we have negative e b over m square y so this is minus omega square if you define omega as e b over m okay we have our simple harmonic oscillator differential equation...