00:01
Hello, so here we are given that u1, u2, u3, up to un is going to be an orthonormal basis for rn, and a can be expressed as while c1u1u1 transpose plus c2 u2 u2 transpose and so on up to cn plus cn -n -un transpose.
00:22
I want to show here that a is symmetric and it has eigenvalue c1, c2 up to cn.
00:27
Okay, while showing that a is symmetric, we just take the transpose of a.
00:33
In doing so, we get that a transpose is given here.
00:39
It's then going to be equal to c1 u1 transpose all transpose plus c2 u2 u2 transpose and so on, up to cn, un, un transpose, all transpose.
00:51
Since we have that p plus q transpose is equal to p transpose plus q transpose.
00:56
So we can continue on and get that a transpose is equal to a.
01:00
So we get here that a transpose is equal to a.
01:05
So therefore we are symmetric.
01:09
We have that a is symmetric...