The horizontal component, $v_x$, is given by $v_0 \cos 55^{\circ}$ and the vertical component, $v_y$, is given by $v_0 \sin 55^{\circ}$.
So, $v_x = 25 \, \text{ft/s} \times 0.574 = 14.35 \, \text{ft/s}$ and $v_y = 25 \, \text{ft/s} \times 0.819 = 20.48 \,
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