00:01
Continuing on with physical chemistry, with the fast part here, the mass of the isotope at any time can be calculated as the product of the concentration of the isotope and its volume v.
00:10
So in equation form, what i mean by this is the mass of isotote equal to v in liters multiplied by c, milligrams, isotote per liter.
00:30
So we can write the balance on the isotope as follows.
00:33
So we have accumulation is the negative of consumption.
00:40
So we have d over d, t, b, c is equal to negative kc, mg over l multiplied by s units, vl units, where dc over dt is equal to negative kc, with the initial conditions being t equals zero and c equals c -0.
01:03
So in the next step, we can integrate the direction, what we get is integrate within the limits c 0 and c, d c over c is equal to integral between t and 0 negative kdt.
01:23
So what we get is lnc for c0 is equal to negative kt, where t is equal to negative lnc over c not, all divided by k, where t 1 ,000, where t 1 ,000, is equal to negative l n 0 .5 over k.
01:45
T1 .5, therefore, is equal to ln2 over k...