00:01
If a railroad car were to spill 26 tons of concentrated sulfuric acid that would not be a good thing as sulfuric acid is both a strong acid and a strong oxidizer, if concentrated sulfuric acid is 98 percent, then we have 98 grams of sulfuric acid per 100 grams of the solution.
00:21
To calculate molarity, we need to convert the grams of sulfuric acid into moles of sulfuric acid by dividing by the molar mass of sulfuric acid.
00:30
Then we can convert the grams of solution into mill liters of solution using the density, which was given to us at 1 .836 grams per mill liter.
00:39
And then last of all, convert the milliliters of solution into liters of solution.
00:44
And we get 18 .3 molar sulfuric acid.
00:50
For part b, we're going to attempt to neutralize this spill with sodium carbonate.
00:58
So what we need to do is figure out the moles and then the mass of sodium carbonate that are required.
01:04
We'll start with the 26 tons of sulfuric acid, convert the tons into kilograms sulfuric acid, and then the kilograms of the solution into actual kilograms of just the sulfuric acid.
01:18
If it's 98 percent, then for every one kilogram of the solution we have 0 .98 kilograms of pure sulfuric acid.
01:27
We can then convert the kilograms into grams and using the molar mass of sulfuric acid, the grams of sulfuric acid into moles of sulfuric acid.
01:36
Now the neutralization reaction comes into place...