00:01
In this exercise, we're going to be considering a random sample that is drawn from a normally distributed population, and we know the standard deviation equals 10 .7.
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For this sample, we're going to construct a 95 % confidence interval for the population mean, based on the given information.
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And we have two cases, case a, where we're given that the sample size is 25.
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The sample mean is 103 .3 .3.
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And the sample standard deviation is 11 .0.
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Then we're going to look at a different case that has a smaller sample size, but the mean and the standard deviation for the samples are the same.
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So let's start.
00:44
And first of all, write the formula that we need to use to solve for the 95 % confidence interval.
00:53
And in this case, since the population standard deviation is known, we're going to use the following formula.
01:01
To have x bar plus or minus the critical value for z for a two -tail test corresponding to the given level of significance multiplied by the population standard deviation divided by the square root of the sample size n so what we want to do now is to substitute the values in each case so for the first case we're going to have 103 .3 which is the mean plus or minus the critical value of z in this case is going to be obtained as follows, we're going to consider the level of significance alpha equals 1 minus 0 .95, which equals 0 .05...