00:01
In this question, it is given that there is an inclined plane which is making an inclination of 30 degree with respect to horizontal.
00:13
On this inclined plane, there is a rectangular box filled with water.
00:22
This rectangular box is moving upwards with an acceleration of 3 meter per second square.
00:35
Now we need to determine the slope of the free liquid surface.
00:40
Consider this is the free liquid surface on which let us consider a fluid particle.
00:52
Let us say o.
00:54
On this particle, what will the forces be acting? the force due to the acceleration, f, and the pressure force.
01:11
That is, the force due to the pressure is acting.
01:15
Apart from these two forces, the weight of the fluid particle will be acting in the vertically downward direction.
01:21
So there are three forces.
01:24
One is the force due to acceleration, we can say that f is equal to ma and w is the weight of the fluid particle, that is f is equal to moss -hid acceleration due to gravity and the force due to pressure.
01:43
P is equal to pressure multiply with area.
01:49
Okay.
01:53
This is the angle.
01:55
Theta which we need to determine.
01:56
Let us say the inclined plane is making an inclination of 30 degree to the horizontal which we will call it as 5 which is 30 degrees.
02:14
If this is theta then this will be theta.
02:22
Why because this is a horizontal line and this is the vertical end and this is an inclined plane or we can say that free liquid surface.
02:34
The free liquid surface is making an inclination of theta with respect to horizontal.
02:38
That is the case definitely because of the alternate angles.
02:43
This will be theta.
02:45
Now if we consider the force f, this force will have two components.
02:50
One will be the horizontal component fh and another will be the vertical component fy...