00:02
In the given problem, there is a uniform magnetic field in horizontal direction shown like this.
00:16
The magnitude of this magnetic field is given as 0 .050 tesla.
00:24
Then there is a rectangular current carrying loop kept in this magnetic field like this.
00:33
This loop is carrying a current in counterclockwise direction like this.
00:53
This loop is named as a, b, c and d.
01:02
The dimensions of this loop are given as here.
01:06
The length of this loop is 20 cm and its width is given as 10 centimeter.
01:18
The current passing through this loop is having a magnitude of 2 .0 ampere.
01:27
Now in the first part of the problem we have to find and the force, magnetic force is experienced by all these four arms of this loop.
01:38
First of all, for the force acting at the arm ab and using the expression for this force in vector form, it is given as il means current element in vector form.
01:52
So for l it will be ab.
01:55
This is iab across the magnetic field in vector form.
02:01
So here it will come out to be fab is equal to i into a b the length of the wire into b here this b is for magnetic field into sine 90 degree as these two are perpendicular to each other.
02:16
So finally plugging in all known values for the current this is 2 .0 amper for length of the wire this is 20 centimeter or 20 by 100 meter multiplied by the magnetic field which is 0 .5...