Question
A red line (wavelength $630 \mathrm{~nm}$ ) in the third order overlaps with a blue line in the fourth order for a particular grating. What is the wavelength of the blue line?
Step 1
We know that the grating equation is given by: $n \lambda = d \sin \theta$, where $n$ is the order, $\lambda$ is the wavelength, $d$ is the grating spacing, and $\theta$ is the angle of diffraction. Show more…
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