(a) Reference [561] (as cited in [560]) used experimental data measured using a human eye with 3.0 mm pupil diameter to obtain an analytic fit to the line spread function: $I(i)=0.47 \exp \left(-3.3 i^2\right)+0.53 \exp (-0.93|i|)$. The distance on the retina from the fovea is $i$, in arc min. Show that Fig. 11.30 accurately plots this function.
(b) Plot on this same set of axes this same function after each point has been broadened by 1 arc min , and compare them. (One relatively crude, way to do this is divide the $x$-axis into bins that are 0.1 arc min wide, so you have a set of rectangles that have heights $I(i)$ and widths 0.1 arc min centered at $i=0.0, \pm 0.1, \pm 0.2, \pm 0.3, \ldots$ arc min. Replace these by rectangles with widths of 1.0 arc min . Sum the contributions at each $i$ and then normalize all points by the value at $i=0$. This can be made less crude by using a smaller width or a broadening function that is smoother than a rectangle.)