00:01
In this question, we have this setup.
00:04
So there's a charge rod with a non -uniform charge distribution with lambda equals to alpha x.
00:10
And so there are two parts in the question.
00:13
In part a, we want to find out the units of alpha.
00:17
And part b, want to find the electrical potential at point a.
00:23
So to do the, to find the units of alpha, you'll start with lambda equals to alpha x.
00:31
Then we know that lambda is the linear charge density so lambda is coulum per meter and then we know the units of x which is meters so the units of alpha will then be units of lambda divide by units of x and then this gives us pullum per meter square okay so this is the answer for part a and then in part b you want to find the electric potential at point a so and we are dealing with continuous charge distribution.
01:11
So what we will do is to consider a small piece of dq here and this is equal to and then we can calculate the electric potential due to dq at that point.
01:26
A will be using bv equals to ae, dq, over r, okay, and our k -e is 1 over 4 pi, x or not, it's just a constant.
01:40
Okay, and then, so we are going to do integration here to sum up all the contributions by each dq at different, say, different parts of the rod, okay, and right now with dq first...