00:01
Everyone here it is given.
00:02
Monoatomic gas undergoes process a2b isochoric, v2c, isothermal and c2a isoberic.
00:42
And a volume is 5 litre pressure is 1 atmosphere and temperature is 300 kelvin.
00:57
In the first part we have to find the temperature at b and b part temperature at c, in c part temperature at c and d part volume at c.
01:20
Discuss experimental method to achieve process a to b, b to c and c to a.
01:53
We have to calculate amount of heat transfer.
01:59
Work done and change in internal energy in each process we have to find total amount of heat energy transfer in a cycle work done in a cycle and change in internal energy of the cycle changing internal energy of the cycle so all these parameters we have to calculate first part using gas equation pb is equal to nr t number of moles can be related as pressure at a point into volume at a point divided by r into temperature at a point substituting the value pressure at a 1 .013 10 to the 4 5 volume volume is 5 liter but we are using in meter cube gas constant 8 .314 into 300 kelvin so answer of a part you will get 0 .203 now b part, temperature at b, a to v is isochoric process.
03:41
So, delta v is zero and temperature will be directly proportional to pressure.
03:49
So we can say temperature at b point will be temperature at a.
03:55
Pressure at b upon pressure at a, that is 300, 3 upon 1.
04:01
So it will be 900 kelvin.
04:06
Now, c point b2c is isothermal process so temperature is constant hence temperature at c will be also 900 kelvin d point c2a pressure is constant so volume is directly overshunded to temperature.
04:48
So volume at b will be sorry volume at c 15 liter e point.
05:52
A to b process can be obtained by fixing the position of piston b2c can be obtained by keeping the system inside over at nac and ended carbon and c2a can be obtained by piston to be kept free in atmosphere.
07:33
Now we have to discuss the f point change in internal energy.
07:38
So we will find the internal energy in each internal energy at a will be ncb temperature at a monotomics 3x2 r into 300 calvin substitute the value number of moles 0 .203 3 by 2, 8 .314...