00:02
This problem is discussing the thermal cycle.
00:08
The thermal cycle, which is we start from state a.
00:14
Do the constant volume to state b, state a to state b, and do the ethosothermal process to state c.
00:29
And at this point, the same plagiar as a, then do the isovaric.
00:37
Isobaric and go back to state a.
00:44
This is the process of this cycle.
00:51
So now, for part a, what's the number of modes for this gas? now, from n equal to pv, rt.
01:13
Now, we already know the pressure is 180n, and the volume is 5 liters.
01:27
The temperature is 300 constant, 300 kelvin.
01:41
So this is 0 ,203 more.
01:47
This is number more of the gas.
01:51
Okay, now for part b, what's the temperature of each state? now we know the temperature at a is equal 300.
02:08
Kelvin.
02:12
And now we do the constant volume to state b.
02:19
So at this condition, we know that temperature b will be equal to n, r and p at b and v at b.
02:36
So for a problem we already know the pressure b is 380m at this time.
02:51
And the volume b is also 5 liters because it is constant volume.
03:07
The n, we already know from part a, you know, and the constant.
03:13
So here we can get the temperature at the b is 900 kelvin.
03:22
Now, what's the temperature at c? because from b to c is isothermal.
03:33
So this temperature still the same as a c.
03:42
So this is the temperature, a, b, c states.
03:48
And now what's the volume of the state c? we already know from b to c is aothermal.
04:01
I follow so should be followed the p -b -vb must be equal to pcvc.
04:12
So v -c will be the pbv -b -pc.
04:25
So what's the pb? pb is 380m and the volume is 5.
04:32
And the pc right now is 1 -80m.
04:35
So it is 50.
04:39
Okay, this is volume of c.
04:46
This is the temperature b and c.
04:51
Okay, this is temperature a.
04:55
This is a number of more.
04:57
Okay, now let's see the part c.
05:03
What is the part c? parts is to find out all the internal energy for each state.
05:09
Okay, now we know the internal energy.
05:16
We start from here.
05:19
It's ncvt.
05:22
This is internal energy.
05:24
So now, internal energy a will be ncvt.
05:33
That should be the more number is 0 .203.
05:41
And what's the cv? the cv, because this is monotomic, so the cv should be three -half times up.
05:51
R is 8 .3 .1 and now the temperature is 300.
06:03
So this will be 759 joules.
06:12
This is the a, okay, internal energy for a.
06:18
And why is the internal energy for b? for b will be same number of more times three high.
06:35
R times the temperature.
06:40
So this will be 2 ,277 joules.
06:49
This is the internal energy.
06:56
State b.
06:57
Now, what's the internal energy? for c, the c is will be same number of more, 3 .5, r, and now the temperature c is 3 .5, r, and now the temperature c is at c is 900.
07:24
So this will be the same.
07:30
2277 jewel.
07:32
2 ,277, 77.
07:38
Okay, this is the internal energy for c.
07:43
So we already have those data that's build up the table.
07:54
The table is, we want to know a, b, say b, c, and what's the pressure, volume, temperature, and the internal energy.
08:23
So, the pressure at a is 1 .80m.
08:29
1 .a.
08:32
Okay.
08:33
B is 380m.
08:35
Okay.
08:38
So the unit is atn.
08:44
Okay, now that will be clear.
08:47
1 .80m, 380m, and this also is 180m.
08:53
And the volume, a is 5, b also is 5, constant volume, and the c is 50...