00:01
For this question, we have some sample of hydrogen atoms irradiated with width length of 85 .5 nanometers.
00:13
Right? and we observe some photoelectrons.
00:20
So basically the atoms are being ironized by this particular photon.
00:28
So we're going to find, assuming that the atoms are in the ground.
00:33
State, we're going to find what is the maximum kinetic energy of these photoelectrons.
00:39
So first off to find the energy of the photon, let's see over lambda, i'm going to use chs 1240ev.
00:48
Nanometers, and we will get the energy of the photon to be 14 .5 ev.
01:04
Now as we know, the ionization energy for hydrogen is 13 .6 ev.
01:12
So this is the amount of energy required to overcome the kulomatraction.
01:17
Any excess energy that is given would be imparted as kinetic energy, right, to the electron...