We can use the formula for power, which is $P = \frac{V^2}{R}$, where $V$ is the voltage and $R$ is the resistance. Substituting the given values, we get:
\[P = \frac{(120 \, \text{V})^2}{0.500 \, \Omega} = 28800 \, \text{W}\]
This means that 28800 Joules of
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