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A short circuit to the grounded metal case of an appliance occurs as shown in Figure 23.60 . The person touching the case is wet and only has a 3.00 $\mathrm{k} \Omega$ resistance to earthl ground. (a) What is the voltage on the case if 5.00 ma flows through the person? (b) What is the current in the short circuitif the resistance of the earth/ground wire is 0.200$\Omega ?(\mathrm{c})$ Will this trigger the 20.0 A circuit breaker supplying the appliance?

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Physics 102 Electricity and Magnetism

Chapter 23

Electromagnetic Induction, AC Circuits, and Electrical Technologies

Electromagnetic Induction

Cornell University

Simon Fraser University

University of Sheffield

Lectures

03:27

Electromagnetic induction …

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so for party weaken. Simply use the OEMs law, the voltages equaling the current multiplied by the resistance. And this would be equaling the current of five milli amps, or five times 10 to the negative. Third amps multiply by the resistance of three Killy alms or three times 10 to the third homes. And so the voltage is found to be 15 volts, and this would be our answer for party four part B. We can say that. Then, um, we're going to calculate the value of current flow in the short circuit. And so we can say that then the current would be equaling the voltage divided by the resistance, and this would be equal to 15 votes. The voltage found party. But now the resistance is equaling 150.2 thumbs. And so this is gonna give us 75 amps. And so essentially, the value of current flow in the short circuit would be 75 amps. That would be your answer for part B. And we can say see, yes, this current will weaken. Say it will trigger the circuit breaker, which supplies the appliance because 75 amps is greater than 20 amps, and this is what it needs to. This is the value. If it's if the current is greater than seven and then 20 amps, it's gonna trigger the circuit breaker in order to, ah, protect the circuits as best as it can. That is the end of the solution. Thank you.

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