00:01
In the first part of this question, we'll show that the energy level differences become smaller and smaller as we go to higher and higher energy levels, which is when n goes to a very large number.
00:18
So we know that in general, the energy level for the hydrogen atom is given as negative 13 .6 e .v divided by n square.
00:31
For an energy that is just one above it, just be an n plus 1, just negative 10 .6v divided by n plus 1 square.
00:50
Now we can find the difference in the energy by just taking the n plus 1 minus n.
01:00
It gives us 1 over n square minus 1 over n plus 1 square.
01:16
Now to simplify this fraction a little bit over here, we can combine them together.
01:25
So we get n plus 1 square, minus n square.
01:33
We open up the brackets a bit.
01:36
This will become n square plus 2 and plus 1, minus away n square.
01:41
We get 2n plus 1 over n square times n plus 1.
01:52
Square.
01:58
Therefore the expression over here becomes 13 .60 times 2n plus 1 over n square times n plus 1 square.
02:12
Now as n goes to a very large number like infinity, 2n plus 1, right? the 1 over here the magnitude will be much much smaller as compared to the value of n.
02:28
Therefore 2 n plus 1 is just approximately just 2n...