00:01
Okay, if you're doing this problem, you have a much better diagram to look at than the one i just drew here.
00:05
But this is the idea.
00:08
Okay.
00:09
So in this problem, a vertical force p magnitude 20k.
00:14
Aps is applied at point c located on the axis of symmetry of a cross section of a short call.
00:21
Knowing y is five inches, i think, let me double check that.
00:25
Knowing y is five inches.
00:29
Determine the stress on a, the stress on b.
00:31
And the location of the neutral axis.
00:35
Let's begin.
00:38
Okay, so first, location of the centroid.
00:49
And that will be, that segment will equal a1y1 plus a2y2 divided by a1 plus y2.
01:03
So this will equal six times two times five plus four times two times two divided by 6 times 2 plus 4 times 2.
01:25
And this will give me when i'm done 3 .8 inches.
01:32
And then the eccentricity of the load will equal 5 minus 3 .8 will equal 1 .2 inches.
01:57
The moment of inertia would be i plus i1 or equals i1 plus i2.
02:14
So i will equal 1 over 12.
02:19
It'll be 6 .2 to the 3rd.
02:23
It'll be plus 12 times 1 .2 times 2 times 2...