00:01
In this question, we have a single -turn current loop.
00:04
The current is 4 ampiers.
00:06
The current loop has a shape of right angle triangle, 50 cm, 120 cm and 130 cm triangle.
00:17
So the magnetic field is uniform.
00:20
It has magnitude 75 metsa so, and the magnetic field is parallel to the currents in the 130 cm side of the wire.
00:30
We want to find the magnitude of the magnetic force on each side of the wire and the next force on the loop.
00:40
So to do this question, we'll be using the formula.
00:48
Fb equals to b -i -l, side data.
00:55
So for part a, for the 130 cm side, data is equal to the 30 -cm side, data is equal to the 0 degrees so fb equals to 0 because sign 0 is 0 okay so this is the answer for part a okay 0 newtons and then for part b um for the 50 cm side based on the diagram that i have drawn so this is our i and then this is our b so this is the angle that we are supposed to look at but it's equivalent to sign of this angle is equal to the sine of the acute angle.
01:50
So the sign of the acute angle, sign data, can use this right angle, triangle, and you get 12 over 13.
02:00
So fb is equal to b -i -l, sign data...