00:01
So in this question, we are given this graph, and this graph, unlike the y versus x graph, we usually see, is a y versus t graph.
00:11
And then what it says is that this is a graph of 1 point at x equals 0 of the sinusoid wave, as it travels over time.
00:23
So let's look at the questions.
00:28
We are given a couple numbers.
00:29
We know it takes a number.
00:30
We know it takes, 10 seconds to travel a whole period.
00:34
We know that maximum minimum amplitude is 4 .0 centimeter, and we know the wave of the wave is 20 centimeter.
00:43
Question a asks, if we draw the y versus x graph, is this graph going to be a positive sign or a negative sign? well, let's look at this.
00:55
Right now we have y versus t graph.
00:58
If we draw a y versus x graph, at first, this point stays at zero, and as times goes by, it goes to positive, and then it go back to normal.
01:14
Well, let's try out what would happen if we have a positive sine wave.
01:19
If we have a positive sine wave, and we know this wave is, let's see, do we know where this wave is traveling? yes, we know this wave.
01:34
Is traveling to the right.
01:39
So if this wave is traveling to the right, what this point would do is that it has this form of this, and then as this wave traveled to the right, you can imagine, well, now it travels to the right, and this point is going to go down, so that is not correct.
01:56
As opposed to, it's a negative sine wave, and then it travels to the right, this point is going to go up.
02:11
And eventually it goes up, it goes down, it goes up, and then it goes to the minimal, and it goes up, which is just as, just like this graph.
02:21
This graph is the position of x, and it goes up, it goes down, it goes to minimal, and then it goes to equilibrium.
02:30
So from this, we can see that a negative side, y -x graph, will best correspond to this y -t graph of this point.
02:45
So i hope that makes sense because yt graph and yx graph are two different types of graphs and even though they look similar, so we present different things and you need to learn to how to respond one to the other okay, so for part b we need to find one max and this is easy because the graph already told us maximum one is four centimeters, so we know this and then we need to find k k is 2 pi over lambda so question told us lambda is 20 centimeter so this is pi over 10, which is 0 .3 .1 radius per centimeter.
03:28
Then we also need to figure out what omega is.
03:31
In order to find omega, we need to figure out.
03:38
So different ways we can find omega, we can find it by using k times v.
03:43
Because then we need to find out v.
03:45
So i find the easiest way to just use a period because we know period is 10 second.
03:50
So omega corresponds to frequency by 2 pi f, and f is 1 over t, so omega is just 2 pi of a period...