00:01
A small sphere with a charge of q1 .8 .00 microculems hanging from a spring and another sphere q2 of negative 0 .6 .0 microcolum is held beneath it.
00:13
The string stretches by 3 .5 centimeters and reaches a new equilibrium with a separation between the charges of 5 .00 centimeters and we're asked to find the force constant of the spring.
00:31
So first of all, we know that the sum of our forces is going to equal zero.
00:37
Hook's law tells us that our spring constant is equal to kx, k is the spring constant, and the force is needed to extend our spring, and our force is equal to k -e times q1, q2, times r -squared.
01:07
Where k is equal to 8 .98 times 10 to the 9th newton meters squared per coulum squared.
01:21
And our given data will be q1 and let's do this in coolums will be 8 .00 times 10 to the minus 7th coolums.
01:37
Q2 will be 6 .00 negative times 10 to the minus 7th coulamps.
01:49
Our d, which is 3 .5 centimeters, will 0 .0 3 .50 meters.
01:59
And our separation will be r, which will be 0 .050 meters.
02:12
Okay.
02:19
So let's take a look at this.
02:22
So i've got a spring hanging from a spring and i've got q1.
02:34
And then i have a spring hanging and i've got q1 and i've got q1 and down here i have q2.
02:51
So here i'll have my spring constant.
02:59
F my charge.
03:02
This will be down...