00:01
Now in this problem we are given that a tiny sphere with a charge of 7 microcoulomb, q is 7 .0 microcoulomb, it is attached at the end of the spring that you can see here in this image.
00:14
Now two other tiny charged sphere each with a charge of minus 4 microcoulomb, so these two charges are there with a charge minus 4 .0 microcoulomb are placed in this position that you can see here.
00:33
Now due to this the spring is stretched by 5 centimeter, this is the x value it is stretched by 5 centimeter from its previous equilibrium position.
00:45
Now we need to find the spring constant k.
00:50
So to solve this problem we're going to use the coulomb slope and the hook slope.
00:55
Now by symmetry we know that the horizontal component of the force cancel each other only the vertical component we're going to consider.
01:02
So first let me draw the figure here.
01:06
So here you can see these are the three charges q and this is small q with the charge minus 4 microcoulomb.
01:16
Now this distance let this be b which we are given to be 4 centimeter and let this distance be a and here also this will be a which we are given to be 2 centimeter.
01:30
Okay now we'll be considering the forces in the y direction.
01:33
So this is the y direction i'm taking.
01:35
Now let's calculate the magnitude of the force in the y direction due to this charge.
01:40
So this is along the y direction let this force be f.
01:44
Now by coulomb slope i can write that f this would be equals to k.
01:49
I'm just taking the magnitude so q times q small q divided by r square times cosine theta.
01:59
Correct? here this is the theta here i'm taking this theta and this is the r.
02:06
Now r from the pythagoras theorem i can write that r square would be a square plus b square and cosine theta this will be equals to b over square root a square plus b square...