00:01
Okay, so we're going to react a strong acid with a strong base, and we're just going to go ahead and make some water.
00:12
To start with, we know that the ph is 13 .68, so our h -plus concentration, this is the ph of our n -a -o -h solution.
00:26
So the h -plus is 2 .1 times 10 of the minus 14 molar.
00:32
And if we change that to hydroxide, right, kw over h plus, will give us 0 .48 molar solution of our oh minus.
00:44
For our strong acid, our perchloric acid, we know we've got 0 .128 molar and 0 .0350 liters.
00:57
So that's going to give us 0 .00448 moles of h -plus.
01:06
Now, when we titrate, that means it's going to require the same amount of oh minus.
01:19
So if we take that and divide it by our molarity, which is 0 .48 molar, which is moles per liter, we'll get our liters of oh minus that we needed to add.
01:31
So 0 .094 liters or 9 .4 milliliters.
01:39
That's the amount of oh minus we needed to add.
01:44
And then we want to know what the ph at the equivalence point, well the ph is 7.
01:51
Ph is 7 at the equivalence point for all strong acid, strong base titrations...