Question
A solution that contains $1.341 \mathrm{~g}$ of $\mathrm{KCl}$ has how many $\mathrm{mEq}$ of $\mathrm{K}^{+}$and $\mathrm{Cl}^{-}$?
Step 1
The molar mass of KCl is calculated by adding the atomic masses of potassium (K) and chlorine (Cl). Molar mass of K = 39.10 g/mol Molar mass of Cl = 35.45 g/mol Molar mass of KCl = 39.10 g/mol + 35.45 g/mol = 74.55 g/mol Show more…
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