00:01
Okay, we've got a buffer, but we also have a fictitious acid.
00:05
So the first thing we're going to need to do is find ka for our acid.
00:11
Okay, so we're given some information about our x minus.
00:18
We know that we have 0 .614 moles, and that's in 2 .5 liters.
00:26
So we have 0 .246 molar.
00:30
So let's go ahead and write the equation for x minus reacting with water to give us hx and oh h minus.
00:41
And we'll set up an ice box.
00:43
Okay, so 0 .246, we don't care about that.
00:48
0 ,0 minus x, plus x and plus x.
00:53
So 0 .246 minus x, x and x.
00:58
Well, we have enough information to figure out what x is.
01:04
So we're told that our solution of x minus has a ph of 8 .73.
01:12
So from that we can get our h plus, right, 10 to the negative 8 .73.
01:17
It's 1 .86 times 10 of the minus 9 molar.
01:22
So we can use that to find the oh minus, right? one times 10 of the minus 14 divided by h plus gives us our oh minus...