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A spaceship, 200 $\mathrm{m}$ long as seen on board, moves by the Earth at 0.970 $\mathrm{c} .$ What is its length as measured by an Earth-bound observer?

$L=48.6 \mathrm{m}$

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in this problem and not equals 200 meters and not his equal to 200 meters and relative speed of this best ship is 0.970 times the speed of light. So relative speed is equal to zero point mine. Ah, 70 times the speed off light. Well, we know it Lend contruction Al is given by a lot Are times square root off one minus we divided by sea whole square obviously is they question for length contraction and uh L A is equal to a lot times scared would've won minus reading by basic old square Well, let's plug it Values l A is equal to a log east 200 meters are times square root off one minus We is you point mine 70 times the speed of light are divided by C All square and therefore l is equal to um but 200 multiplied by screen Ruto one minus 0.9 for one and hence l is equal to 48.6 um meters

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