Question
A spherical drop of water carrying a charge of 30pC has a potential of 500 $\mathrm{V}$ at its surface (with $V=0$ at infinity)(a) What is the radius of the drop? (b) If two such drops of thesame charge and radius combine to form a single spherical drop,what is the potential at the surfaceof the new drop?
Step 1
We can use the formula for the potential at the surface of a charged sphere, which is given by $V = \frac{Q}{4\pi\epsilon_0 R}$, where $\epsilon_0$ is the permittivity of free space and $R$ is the radius of the sphere. Show more…
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A spherical drop of water carrying a charge of 30 pC has a potential of 500 $\mathrm{V}$ at its surface (with $V=0$ at infinity) (a) What is the radius of the drop? (b) If two such drops of the same charge and radius combine to form a single spherical drop, what is the potential at the surface of the new drop?
A spherical drop of water carrying a charge of 30 pC has a potential of 500 V at its surface (with V= 0 at infinity). (a) What is the radius of the drop? (b) If two such drops of the same charge and radius combine to form a single spherical drop, what is the potential at the surface of the new drop?
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