Question
A spherical water drop $50.0 \mu \mathrm{m}$ in diameter has a uniformly distributed charge of $+20.0 \mathrm{pC}$. Find (a) the potential at its surface and (b) the potential at its center.
Step 1
The diameter is given as $50.0 \mu m$, so the radius $r$ would be half of the diameter. Therefore, we have \[ r = \frac{d}{2} = \frac{50.0 \times 10^{-6}}{2} = 25.0 \times 10^{-6} m \] Show more…
Show all steps
Your feedback will help us improve your experience
Prem Bijarniya and 54 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A spherical drop of water carrying a charge of 30 pC has a potential of 500 V at its surface (with V= 0 at infinity). (a) What is the radius of the drop? (b) If two such drops of the same charge and radius combine to form a single spherical drop, what is the potential at the surface of the new drop?
A spherical drop of water carrying a charge of 30 pC has a potential of 500 $\mathrm{V}$ at its surface (with $V=0$ at infinity) (a) What is the radius of the drop? (b) If two such drops of the same charge and radius combine to form a single spherical drop, what is the potential at the surface of the new drop?
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD