Question
A square loop of wire of edge length $a$ carries current $i$. Using the results of Problem 11 , show that, at the center of the loop, the magnitude of the magnetic field produced by the current is$$B=\frac{2 \sqrt{2} \mu_{0}|i|}{\pi a}$$.
Step 1
Step 1: We know that the magnetic field at the center of a wire loop is given by the formula: $$ B=\frac{\mu_{0}i}{4\pi r}\left(\cos\theta_{1}+\cos\theta_{2}\right) $$ where $r$ is the distance from the wire to the point where the magnetic field is being Show more…
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A square loop of wire of edge length $a$ carries current $i$. Show that, at the center of the loop, the magnitude of the magnetic field produced by the current is $$ B=\frac{2 \sqrt{2} \mu_{0} i}{\pi a} $$
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