00:01
So in this question, we are given three particles, right? and the state of these particles are si sub a of x, si sub b of x and si sub c of x, right? and in the question it asks us that suppose that these states are orthoanormal, right? now what we need to do in this question is that we need to construct three particle states that represents three different cases, right? the first case is for the distinguishable particles the second is for identical boson and the last is for identical fermions right now before starting it in the appendix it gives us the information that when we have n particles right so when we have n particles which are fermions so the total wave function it can be written as x1 of x2, x1, x2, so on till it reaches the point x sub n, right? so that is equal to 1 divided by under root n.
01:18
Over here we have si sub a of x1, si sub b of x1, and so on till it reaches the point si sub n of x1, right? similarly, over here we would have si -sub -a of x2, and over here we would have si -sub b of x -2, and so on till it uses the point si -sub -n of x -2, right? so this procedure will go on till the point it reaches si -sci -sab -a, of x -su -a of x -sub -n, right? si sub b of x n till it reaches the point where we have si n and it reaches the point of x of n right and this is known as the this equation right this determinant this whole equation it is known as the slater determinant right so now let's move forward to the solution of this equation the solution is very simple first of all we would solve it for the distinguishable particles of what distinguishable particles total wave function is just the product of it's just the product of two sorry of three wayf functions right of three wave functions so this it has an equation of si x1 x1 x2, x3, that is equal to si sub a of x1, si sub b of x2, and si sub c of x3, right? so this is the complete solution for part a.
03:31
It's very simple, right? it's just one step solution.
03:34
Now we are moving forward to the solution of part b, that is for the identical bosons.
03:39
And the wave, total wave function, for identical bosons, it must be symmetric, right? so it must be symmetric when we permute any two particles, right? so let's take a look at its equation, right? so that would be psi of x1, x2, x3, right? so this is the wave function for three particles in the case of identical bosons.
04:21
Right and this must be symmetric when we permute the permute any two particles right so the right hand side of this equation would be one over and root six square bracket size of a x1 size of b of x2 and si sub c of x3 right plus i'm going to write the next two in the next line, right, that will, that would be for psi sub a x1, si sub c of x2, and si sub b of x3, right? plus we have si sub c of x1, si sub b of x2 and size up a of x3, right? so this was one square bracket, and this equation is still going on, right? i'm going to write the next time over here, so that is plus 1 over under root 6 square bracket again, si sub b of x1, psi sub a of x2 and si sub c of x3...