Two identical bosons or fermions in a state
$$
\Psi^{(2)}=A \sum_{i j} c_i d_j a_j^{\dagger} a_i^{\dagger} \Psi^{(0)}=A \sum_j d_j a_j^{\dagger} \sum_i c_i a_i^{\dagger}|0\rangle
$$
are said to be uncorrelated (except for the effect of statistics). If $\sum\left|c_l\right|^2=$ $\sum\left|d_i\right|^2=1$, determine the normalization constant $A$ in terms of the sum $S=\sum c_i^* d_i$.
(a) In this state, work out the expectation value of an additive one-particle operator in terms of the one-particle amplitudes $c_i$ and $d_i$ and the matrix elements $\langle i|K| j\rangle$.
(b) Show that if $S=0$, the expectation value is the same as if the two particles with amplitudes $c_i$ and $d_i$ were distinguishable.
(c) Work out the expectation value of a diagonal interaction operator in terms of $c_i, d_i$, and the matrix elements $\langle i j|K| k \ell\rangle=V_{i j} \delta_{i k} \delta_{j e}$. Show that the result is the same as for distinguishable particles if the states of the two particles do not overlap, i.e., if $c_i d_i=0$ for all $i$.