A steel cable 3.00 $\mathrm{cm}^{2}$ in cross-sectional area has a mass of 2.40 $\mathrm{kg}$ per meter of length. If 500 $\mathrm{m}$ of the cable is hung over a vertical cliff, how much does the cable stretch under its own weight? Take $Y_{\text { steel }}=2.00 \times 10^{11} \mathrm{N} / \mathrm{m}^{2}$ .