Question
A strip of copper is placed in a uniform magnetic field of magnitude 2.5 T. The Hall electric field is measured to be $1.5 \times 10^{-3} \mathrm{V} / \mathrm{m} .$ (a) What is the drift speed of the conduction electrons? (b) Assuming that $\mathrm{n}=8.0 \times 10^{28}$ electrons per cubic meter and that the cross-sectional area of the strip is $5.0 \times 10^{-6} \mathrm{m}^{2},$ calculate the current in the strip. (c) What is the Hall coefficient 1/nq?
Step 1
Therefore, we can set the electric force $Qe$ equal to the magnetic force $Qv_{d}B$. Here, $Q$ is the charge, $e$ is the electric field, $v_{d}$ is the drift speed, and $B$ is the magnetic field. Show more…
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