00:01
Okay, so we have a solution of ammonia, and we know that the ph of our solution is 11 .55, because this is a basic solution.
00:12
If i subtract that from 14, i can get the p -o -h, so that'll be 2 .45, and then i can get the concentration of hydroxide by just doing 10 to the negative 2 .45, and we'll get the hydroxide ion concentration is 0 .05, and we'll get the hydroxide ion concentration is 0 .0 .0 .5.
00:33
0355 molar.
00:36
So our ammonia is reacting with our water and our typical hydrolysis reaction here.
00:46
So it's going to make ammonium ion and hydroxide because it's a weak base.
00:53
If we look at what's happening through an ice box, we don't know how much nh3 we're going to use to start with.
01:01
We're going to ignore the water and we've got none of these to start with.
01:06
And we know that the hydroxide ion concentration, we just figured it out is 3 .55 times 10 of the minus 3.
01:15
Right.
01:16
So i must have gained 3 .55 times 10 of the negative 3.
01:23
Well, i would need to react and would produce this same amount here.
01:31
So obviously these values are going to be the same.
01:35
And at the same time, i must have used 3 .55.
01:40
Times 10 of negative 3.
01:43
So i end up with x minus 3 .55 times 10 of the negative 3 here.
01:51
So i'm going to go ahead and use our value for kb, which is 1 .8 times 10 to negative 5.
01:59
We'll set that up equal to products over reactants.
02:03
So 3 .55 times 10 to negative 3 .3...