00:01
In this one, we're going to be able to relate the results from the ballistic pendulum to the results that were to find the initial velocity of a bullet that was fired at a block that's hanging from a pendulum that is on a pendulum.
00:18
And the bullet will embed itself in the block and will swing up to some height h.
00:25
And we know from the previous example how to relate the initial velocity of the bullet to that height.
00:32
And we're going to get a result based on some data that was given, and we're going to relate that to the same experiment done.
00:41
But instead of using the ballistic pendulum, we're just going to use projectile motion to calculate the initial velocity of the bullet, and we're going to compare the answers.
00:49
So first, we're going to plug in the values given into the previously known ballistic pendulum equation.
00:57
And so we need to plug in the mass of each object for which we need to convert to kilograms.
01:05
So we divide by a thousand in order to get from grams to kilograms.
01:10
So the mass of the bullet will be 0 .0688 kilograms plus the mass of the block, which is 0 .263 kilograms, and divided by 0 .0688 kilograms.
01:25
All that times the square root of 2 times g, which is 9 .81 .2.
01:28
Meters per second squared times h which we need to convert to meters to get from centimeters to meters you divide by a hundred so this is 0 .0 868 meters you plug this into a calculator you'll find that it's approximately 6 .163 meters per second apologies 6 .3 right ahead of myself approximately 6 .3 meters per second that's our first result using the ballistic pendulum.
02:04
If we use projectile motion equations, we know that from kinematic equations and projectile motion, that the equation of motion for the y -coordinate of anything moving through the air will be negative one -half g, g squared, plus a term that relates to the initial velocity in the y direction.
02:28
But in this case, our bullet is being fired exactly horizontal, so there is no initial velocity in the y direction.
02:37
So that second term would be zero, so there's zero, plus the initial height.
02:44
We do the same thing with the x.
02:46
We know there's no acceleration in the x direction.
02:49
We're neglecting air resistance.
02:51
And so this this will be the initial velocity in the x direction, which we can just label the same thing that we labeled the answer over here, v.
03:03
Sub 1i times t, plus the initial x position.
03:09
And we can move our coordinate system such that this is zero.
03:14
We can start at the origin, wherever the x coordinate of the bullet, wherever it starts, can be zero.
03:21
And so we want to know what this is.
03:25
And what we can measure is the range of the projectile, which we also labeled as x.
03:33
And we can also measure the initial height, which i will call y sub zero, and i'll call this max for the range...