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A telescope can be used to enlarge the diameter of a laser beam and limit diffraction spreading. The laser beam is sent through the telescope in opposite the normal direction and can then be projected onto a satellite or the Moon.(a) If this is done with the Mount Wilson telescope, producing a 2.54-m-diameter beam of 633-nm light, what is the minimum angular spread of the beam?(b) Neglecting atmospheric effects, what is the size of the spot this beam would make on the Moon, assuming a lunar distance of $3.84 \times 10^{8} {m} ?$

A. $\theta=3.04 \times 10^{-7} \mathrm{rad}$B. 235 $\mathrm{m}$

Physics 103

Chapter 27

Wave Optics

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part eight off the given problem. The minimum spirit off the beam is given by that, uh, Isaac all to 1.22 times Linda de my Katie. So 1.22 times Linda, we hear 6.33 times 10 to the power minus seven meters. Derided by Devi hair is 2.54 meters. So simplifying this we get the better ingredients, which is 3.4 times 10 to the power. A minus seven radiance In Bobby, we can find a D small D capital the plus two. Why, then this becomes a D plus too wise to X. So why is it all the extractor then? We can just simply substitute the values, which is a 2.5 for the diameter off the task, or plus two times off X is the distance 3.84 times to about eight times the better. Which we found is to be you going for 04 times stint about minus seven radiance. So I'm applying these old numbers. So these men applying these numbers and aiding them, we'd, uh, 2.54 Gives us 2 35 meter

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