(a) The fraction of gas molecules which traverses distances exceeding the mean free path without collision is just the probability to traverse the distance $s=\lambda$ without collision.
Thus
$$
P=e^{-1}=\frac{1}{e}=0.37
$$
(b) This probability is
$$
P=e^{-1}-e^{-2}=0 \cdot 23
$$