00:01
Hello there, i see we have two parts to this question.
00:05
So let's start with the first one.
00:06
The first one is the ph of the coli cytosol is about 7 .6 to 7 .8.
00:16
So we'll bring, let's write that down because the first clue they bring up is the ph of the coli cytosol is 7 .6 to 7 .8.
00:33
That's the point.
00:35
And then they want to know how many free protons per cell does this equate to.
00:45
So they want to know how many free protons per cell does it equate to.
00:58
So how are we going to solve this? well let's start with the first part when it comes to solving for the ph.
01:05
So we know that ph is equal to negative log times our hydrogen.
01:17
So the number we'll use, let's use 7 .6.
01:26
Okay so how we're going to go about this, we're going to write down 7 .6 equals negative log times our hydrogen.
01:39
So we're going to write down for our antilog, so our antilog of negative 7 .6.
01:55
So we're going to put a negative in front of it because that's our antilog because we move, basically the log comes over that.
02:01
Yeah and that will equal to our hydrogen.
02:07
Okay so with that, that would be our hydrogen plus equal to our 2 .5 times 10 minus 8 ions.
02:29
My bad, i wrote really small.
02:31
So this would be your number of free protons.
02:44
So that's how you solve for part a.
02:49
So you just do the antilog.
02:51
So if you don't know how to do that in your calculator, you just get your calculator and you just hit the second...