0 \times 10^{-12} \mathrm{m}$, we can rearrange the equation to solve for $\Delta v_y$:
$\Delta v_y \geq \frac{h}{4\pi \cdot \Delta y}$
Plugging in the values for Planck's constant ($h = 6.626 \times 10^{-34} \mathrm{J \cdot s}$) and the uncertainty in position,
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