Question
A thin insulating rod is bent into a semicircular are of radius $a,$ and a total electric charge $Q$ is distributed uniformly along the rod. Calculate the potential at the center of curvature of the are if the potential is assumed to be zero at infinity.
Step 1
Therefore, the linear charge density $\lambda$ is given by $\lambda = \frac{Q}{L}$, where $L$ is the length of the semicircular rod. The length of a semicircular rod of radius $a$ is $L = \pi a$. Show more…
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