The absolute pressure is the gauge pressure plus the atmospheric pressure. In this case, the atmospheric pressure is $14.7 \, \mathrm{lb/in}^2$. So, the initial absolute pressure $P_{\text{initial}}$ is $32 \, \mathrm{lb/in}^2 + 14.7 \, \mathrm{lb/in}^2 = 46.7 \,
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