A train passes a railway bridge 150 m long in 18 seconds. If the train is running at a speed of

Name: Problem 5, Chapter 15: The Pearson Guide to Objective Arithmetic for Competitive Examinations
Uploaded: 2021-06-07T18:06:08-08:00
Duration: 1 min 34 s
Channel: Satpal Satpal
Description: A train passes a railway bridge 150 m long in 18 seconds. If the train is running at a speed of 60 km / hr., then the length of the train in metres is (a) 160 m (b) 150 m (c) 180 m (d) None of these

step 1 As we know that the total distance traveled in this case is total distance traveled by train in

Question

A train passes a railway bridge $150 \mathrm{~m}$ long in 18 seconds. If the train is running at a speed of $60 \mathrm{~km} / \mathrm{hr}$., then the length of the train in metres is (a) $160 \mathrm{~m}$ (b) $150 \mathrm{~m}$ (c) $180 \mathrm{~m}$ (d) None of these

   A train passes a railway bridge $150 \mathrm{~m}$ long in 18 seconds. If the train is running at a speed of $60 \mathrm{~km} / \mathrm{hr}$., then the length of the train in metres is
(a) $160 \mathrm{~m}$
(b) $150 \mathrm{~m}$
(c) $180 \mathrm{~m}$
(d) None of these

The Pearson Guide to Objective Arithmetic for Competitive Examinations

Dinesh Khattar 2nd Edition

Chapter 15, Problem 5

Instant Answer

Solved by Expert Satpal Satpal

06/07/2021

Step 1

To convert km/h to m/s, we use the conversion factor: \[ 1 \text{ km/h} = \frac{1000 \text{ m}}{3600 \text{ s}} = \frac{1}{3.6} \text{ m/s} \] Thus, \[ 60 \text{ km/h} = 60 \times \frac{1}{3.6} \text{ m/s} = \frac{60}{3.6} \text{ m/s} \approx 16.67 \text{ Show more…

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A train passes a railway bridge $150 \mathrm{~m}$ long in 18 seconds. If the train is running at a speed of $60 \mathrm{~km} / \mathrm{hr}$., then the length of the train in metres is (a) $160 \mathrm{~m}$ (b) $150 \mathrm{~m}$ (c) $180 \mathrm{~m}$ (d) None of these

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Key Concepts

Speed Conversion

Converting speed from km/hr to m/s is crucial for consistency in calculations. This conversion allows us to work with the same units when using the relationship between speed, distance, and time, typically by multiplying the km/hr value by 5/18 to obtain the speed in m/s.

Total Distance Covered While Passing an Object

When a moving object like a train passes a stationary object such as a bridge, the total distance covered during the crossing is equal to the sum of the lengths of the train and the bridge. This concept is important because it establishes how much distance the train must travel before its entire length has passed the stationary object.

Time-Distance Relationship

The basic time-distance relationship, expressed as distance = speed × time, is fundamental in solving problems involving motion. It is used to determine unknown quantities when two of the variables (speed, time, or distance) are provided.

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